Question

$O$ is the centre of circle. $RQ$ is tangent to circle at $Q$ and $RP$ is tangent to circle at $P$.

$OP=5cm$, $PQ=8cm$, $OM\perp PQ$

Find $MQ$.

• A. $3cm$
• B. $4cm$
• C. $5cm$
• D. $8cm$

Answer 1

Answer: (B)

$4cm$

Perpendicular from the center to the chord bisects the chord.

$\therefore PM=MQ=\frac{1}{2}PQ=\frac{1}{2}\times 8=4$ cm.

So, option B is correct.