Question

$O$ is the centre of the circle $2$ area of sector $APBO$ is $\frac{5}{18}$ of Area of circle find the value of $x$.

Answer 1

Given,

area of sector $=\frac{5}{18}\times$ area of circle

$\therefore \pi r^2\times \frac{x}{{360}^{\circ }}=\frac{5}{18}\times \left(\pi r^2\right)$

$\frac{x}{{360}^{\circ }}=\frac{5}{18}$

$\Rightarrow 18x=5\times {360}^{\circ }$

$\therefore x={100}^{\circ }$