O is the centre of the circle. AD and BC are perpendicular to XY. CB cuts the circle at E, then which of the options are correct?

BE=AD

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CD=CE

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AD=CE

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BD=BE

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Solution

The correct option is C
AD=CE

$∠ A E B = 90^{\circ}$ (angle is a semi-circle)

$∠ A E C = 90^{\circ}$

So, AECD is a rectangle

So, AD=CE

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Similar questions

∠ A

△ A D C \sim △ B E C

C A \times C E = C B \times C D

△ A B C \sim △ D E C

C D \times A B = C A \times D E

A circle with centre O, diameter AB and a chord AD is drawn. Another circle is drawn with AO as diameter to cut AD at C, then BD = 2 OC.

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