Question

O is the centre of the circle and AB is a chord. AC is the bisector of $\angle OAB,\angle OAB={56}^{\circ }$. Find $\angle OBE$.

• A. ${62}^{\circ }$
• B. ${118}^{\circ }$
• C. ${56}^{\circ }$
• D. ${124}^{\circ }$

Answer 1

The correct option is D ${124}^{\circ }$

$\angle OAB={56}^o$ (given)

$\angle OAB=\angle OBA$ (OA = OB = radius and hence $△OAB$ is isosceles)

$\Rightarrow \angle OBA={56}^o$

$\therefore$ $\angle OBE=180-56={124}^o$