The correct option is B 90 In triangle OCA nbsp; ∠OCA = ∠OAC angles opposite to equal sides (OC = OA= radius) And, OC ⊥ BCD ( tangent to a circle is always ...

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Triangle and Sum of Its Internal Angles

BAC ±-Δ

Question

O is the centre of the circle and BCD is the tangent to it at C. $∠ B A C + ∠ A C D$ =

180

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Solution

The correct option is B 90

In triangle OCA
$∠ O C A = ∠ O A C$
{ angles opposite to equal sides (OC = OA= radius)}
And,
OC $⊥$ BCD ( tangent to a circle is always perpendicular to the radius at that point )
So,
$∠ O C A + ∠ A C D = 90^{\circ}$
But,
$∠ O C A = ∠ O A C$
So, $∠ A O C ∠ A C D = 90^{\circ}$

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O is the centre of the circle and BCD is the tangent to it at C. ∠BAC+∠ACD=

The correct option is B 90 In triangle OCA ∠OCA=∠OAC { angles opposite to equal sides (OC = OA= radius)} And, OC ⊥ BCD ( tangent to a circle is always perpendicular to the radius at that point ) So, ∠OCA+∠ACD=90∘ But, ∠OCA=∠OAC So, ∠AOC∠ACD=90∘

O is the centre of the circle and BCD is the tangent to it at C. $∠ B A C + ∠ A C D$ =