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Question

O is the centre of the circle having radius 5 cm. OM chord AB. If OM=4 cm, then the length of the chord AB is

A
6 cm
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B
5 cm
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C
8 cm
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D
10 cm
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Solution

The correct option is A 6 cm
Radius, OA=OB=5cm
OM=4cm
Now,
OA2=AM2+OM2
=>52=AM2+42
=>AM2=25+16
=>AM2=9
=>AM=3
Now, we know that dropped from the centre of the circle to the chord bisect the chord.
Therefore,
AB=AM+MB
=>AB=2AM
=>AB=2×3
=>AB=6cm
299821_244417_ans.png

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