O is the centre of the circle having radius 5 cm. OM⊥ chord AB. If OM=4 cm, then the length of the chord AB is
A
6 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A6 cm Radius, OA=OB=5cm OM=4cm Now, OA2=AM2+OM2 =>52=AM2+42 =>−AM2=−25+16 =>AM2=9 =>AM=3 Now, we know that ⊥ dropped from the centre of the circle to the chord bisect the chord. Therefore, AB=AM+MB =>AB=2AM =>AB=2×3 =>AB=6cm