O is the circumcenter of ΔABCandR1,R2andR3are the radii of the circumcircles of the triangles OBC, OCA and OAB. Then aR1+bR2+cR3= .
A
4abcR3
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B
8abcR3
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C
abcR3
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Solution
The correct option is CabcR3 If O is the circumcenter of Δ ABC, then OA = OB = OC = R LetR1,R2andR3bethecircumradiiofΔOBC,ΔOCAandΔOABrespectively.InΔOBC,2R1=asin2AoraR1=2sin2AorbR2=2sin2BandcR3=2sin2C⇒aR1+bR2+cR3=2(sin2A+sin2B+sin2C)=8sinAsinBsinC(∵sin2A+sin2B+sin2C=4sinAsinBsinC)=8a2R×b2R×c2R=abcR3