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Question

O is the orthocentre of ABC. If BAC=70, then BOC=


A

140

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B

110

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C

100

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D

120

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Solution

The correct option is B

110


Since, AD, BE and CF are altitudes.

ADBC, BEAC and CFAB

In quadrilateral, AFOE:

AFO=90, AEO=90 and FAE=70 [Given]

AFO+AEO+FAE+FOE=360 [Sum of the angles of a quadrilateral is 360]

90 + 90 + 70 + FOE = 360

FOE =360 - 90- 90 - 70 = 110

Now, FOE and BOC are vertically opposite angles.

FOE=BOC

BOC=110


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