wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If O is the point of intersection of two chords AB and CD of a circle such that OB=OD, then prove that triangles OAC and ODB are similar.


Open in App
Solution

Given O is the point of intersection of two chords AB and CD of a circle such that OB=OD

In OAC and ODB

CAB=CDB ( Angle on the common arc BC of a circle are equal )

Similarly

ABD=ACD ( Angle on the common arc AD of a circle are equal )

By AA criteria it can be conclude OAC and ODB are similar.

Hence, triangles OAC and ODB are similar.


flag
Suggest Corrections
thumbs-up
8
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circles and Their Chords - Theorem 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon