CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relative Velocity

O. The positi...

Question

O. The position of a particle moving in a straight line is given by y=3t^3+ t^2+5 (where y is in cm and t is in second),then find the acceleration of the particle at time t=2 s

Open in App

Solution

Suggest Corrections

thumbs-up

92

Similar questions

Q. A particle moves in a straight line with an acceleration a

{m s}^{- 2}

t

a = - \frac{1}{t^{2}}

t = 1 s

the particle has a velocity of

3 {m s}^{- 1}

then the velocity at

t = 5 s

m \times 10^{- 2} m / s

m

is an positive integer). Find

\frac{| m |}{5}

Q. A particle moves in a straight line with an acceleration

a {m/s}^{2}

t

a = - \frac{1}{t^{2}}

t = 1 s

the particle has velocity

3 m/s

then the velocity at

t = 4 s

x \times 10^{- 2} m/s

x

is positive integer. The value of

x / 5

Q. A particle is moving in a straight line whose position varies with time as

x = 8 t^{2} + \frac{2}{π} sin π t

, where x is in meter and t is in second. Then the position, velocity and acceleration of a particle at

t = 4

s respectively are?

Q. The coordinates of a moving particle at any time

^{'} t^{'}

x = t^{3}

y = 4 t^{2}

x

y

are in metre and

t

in second. The acceleration of the particle at time

t = 1 s

Q. A particle moves in a circle of radius

4 cm

at a speed given by

v = t^{2}

v

cm/s

t

seconds

. Total acceleration of the particle at

t = 2 second

2 \sqrt{n} {cm/s}^{2}

, then value of

n

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Relative Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

Relative Velocity

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon