Question

OA is an object with height $4cm$ and O'A' is the image of the object. Find the image height and nature of the image formed.

• A. $3cm$, Erect
• B. $2cm$, Inverted
• C. $4cm$, Inverted
• D. $3cm$, Inverted

Answer 1

The correct option is B

$2cm$, Inverted

Given:
Image distance, $u=-30cm$
Object distance, $v=15cm$
Object height, $h=4cm$

Let height of image be $h^{\prime }$

From magnification formula,
$m=\frac{v}{u}=\frac{h^{\prime }}{h}$
$\frac{+15}{-30}=\frac{h^{\prime }}{4}$
$h^{\prime }=-2cm$

So, the height of the image is $2cm$ and negative sign represents that the image is inverted.