OA is an object with object size $4 c m$ and O'A' is the image of the object. Find the height of the image formed.

$3 c m$

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$2 c m$

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$4 c m$

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$3 c m$

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Solution

The correct option is B
$2 c m$

Given:
Object size, $h_{o} = 4 c m$
Object distance, $u = - 30 c m$
Image distance, $v = 15 c m$
Let image size be $h_{i}$ .

Magnification of a lens is given by:
$m = \frac{v}{u} = \frac{h_{i}}{h_{o}}$
$\frac{+ 15}{- 30} = \frac{h_{i}}{4}$
$h_{i} = - 2 c m$

Hence, image height is $2 c m$ and negative sign shows that the image is inverted.

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OA is an object with object size 4 cm and O'A' is the image of the object. Find the height of the image formed.

The correct option is B 2 cm Given: Object size, ho=4 cm Object distance, u=−30 cm Image distance, v=15 cm Let image size be hi. Magnification of a lens is given by: m=vu=hiho +15−30=hi4 hi=−2 cm Hence, image height is 2 cm and negative sign shows that the image is inverted.

OA is an object with object size $4 c m$ and O'A' is the image of the object. Find the height of the image formed.