OA is an object with object size $4 c m$ and O'A' is the image of the object. If the distance of object and image from the optical center is 30cm and 15cm respectively. Find the height of the image formed.

$3 c m$

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$2 c m$

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$4 c m$

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$3 c m$

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Solution

The correct option is B
$2 c m$

Given:
Object size, $h_{o} = 4 c m$
Object distance, $u = - 30 c m$
Image distance, $v = 15 c m$
Let image size be $h_{i}$ .

Magnification of a lens is given by:
$m = \frac{v}{u} = \frac{h_{i}}{h_{o}}$
$\frac{+ 15}{- 30} = \frac{h_{i}}{4}$
$h_{i} = - 2 c m$

Hence, image height is $2 c m$ and negative sign shows that the image is inverted.

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