OA is an object with object size $4 c m$ and O'A' is the image of the object. If the distance of object and image from the optical center is 30cm and 15cm respectively. Find the height of the image formed.

$4 c m$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$2 c m$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$3 c m$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$3 c m$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$2 c m$

Given:
Object size, $h_{o} = 4 c m$
Object distance, $u = - 30 c m$
Image distance, $v = 15 c m$
Let image size be $h_{i}$ .

Magnification of a lens is given by:
$m = \frac{v}{u} = \frac{h_{i}}{h_{o}}$
$\frac{+ 15}{- 30} = \frac{h_{i}}{4}$
$h_{i} = - 2 c m$

Hence, image height is $2 c m$ and negative sign shows that the image is inverted.

Suggest Corrections

Similar questions

OA is an object with object size $4 c m$ and O'A' is the image of the object. If the distance of object and image from the optical center is 30cm and 15cm respectively. Find the height of the image formed.

OA is an object with object size $4 c m$ and O'A' is the image of the object. Find the height of the image formed.

O A

is an object with size

4 c m

and

O^{'} A^{'}

is the image of the object. The height of the image is and it is.

OA is an object with image size 4 cm and O'A' is the image of the object. Find the image height and nature of the image formed.

OA is an object with height $4 c m$ and O'A' is the image of the object. Find the image height and nature of the image formed.

Join BYJU'S Learning Program

OA is an object with object size 4 cm and O'A' is the image of the object. If the distance of object and image from the optical center is 30cm and 15cm respectively. Find the height of the image formed.

The correct option is B 2 cm Given: Object size, ho=4 cm Object distance, u=−30 cm Image distance, v=15 cm Let image size be hi. Magnification of a lens is given by: m=vu=hiho +15−30=hi4 hi=−2 cm Hence, image height is 2 cm and negative sign shows that the image is inverted.

OA is an object with object size $4 c m$ and O'A' is the image of the object. If the distance of object and image from the optical center is 30cm and 15cm respectively. Find the height of the image formed.