OA is an object with size $4 c m$ and O'A' is the image of the object. Find the image height and nature of the image formed.

3 cm, erect

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2cm, inverted

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4 cm, inverted

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3cm, inverted

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Solution

The correct option is B
2cm, inverted

Magnification = $\frac{v}{u}$ = $\frac{h^{i}}{h}$ where v and u are the image and object distance.

$\Rightarrow$ $\frac{+ 15}{- 30}$ = $\frac{h^{i}}{(4)}$

$h^{^{'}}$ = $\frac{- 4}{2}$ = - 2 cm

Image height is 2 cm and inverted.

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OA is an object with size 4 cm and O'A' is the image of the object. Find the image height and nature of the image formed.

The correct option is B 2cm, inverted Magnification = vu = hih where v and u are the image and object distance. ⇒ +15−30 = hi(4) h′ = −42 = - 2 cm Image height is 2 cm and inverted.

OA is an object with size $4 c m$ and O'A' is the image of the object. Find the image height and nature of the image formed.

The correct option is B
2cm, inverted

Magnification = $\frac{v}{u}$ = $\frac{h^{i}}{h}$ where v and u are the image and object distance.

$\Rightarrow$ $\frac{+ 15}{- 30}$ = $\frac{h^{i}}{(4)}$

$h^{^{'}}$ = $\frac{- 4}{2}$ = - 2 cm

Image height is 2 cm and inverted.