Observation No- Time in minute Px in mm of Hg 1 0 800 2 100 400 3 200 200At constant temperature and volume X decomposes as 2Xg- 3Yg-2Zg - where Px is the partial pressure of X- What is the order of reaction with respect to X-i Find the rate constant-ii Find the time for 75

Applying integrated rate law of first order kinetics #160; k_1=2.303tlog(P_oP_t) =2.303100log(800400) =2.303100 log 2 =6.932× 10^ 3min^ 1 #1 ...

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Standard XII

Chemistry

Mechanism of Adsorption

Observation N...

Question

Observation No. Time (in minute) $P_{x}$ (in mm of Hg)
1 0 800
2 100 400
3 200 200
At constant temperature and volume $X$ decomposes as $2 X (g) \to 3 Y (g) + 2 Z (g)$ , where $P_{x}$ is the partial pressure of $X$ . What is the order of reaction with respect to $X$ ?
(i) Find the rate constant.
(ii) Find the time for 75% completion of the reaction.
(iii) Find total pressure when pressure of $X$ is 700 mm of Hg.

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Solution

Applying integrated rate law of first order kinetics $k_{1} = \frac{2.303}{t} log (\frac{P_{o}}{P_{t}})$

$= \frac{2.303}{100} log (\frac{800}{400})$

$= \frac{2.303}{100} l o g 2 = 6.932 \times 10^{- 3} m i n^{- 1}$
In the two observations the values of rate constant remain same. Therefore it must be following the first order kinetics. Hence order of reaction with respect to $X$ is one.
(i) Rate constant, $k = 6.932 \times 10^{- 3} m i n^{- 1}$
(ii) $6.932 \times 10^{- 3} = \frac{2.303}{t} log (\frac{100}{25})$

$∴ t_{75 %} = 200 min$ .

(iii) $2 X (g) \to 3 Y (g) + 2 Z (g)$
In: $80000$
Fi: $(800 - 2 P) 3 P 2 P$
When the pressure of $X$ is 700 mm of Hg then
$800 - 2 P = 700$
$2 P = 100$
$P = 50$ mm of Hg
Total pressure $= 800 - 2 P + 3 P + 2 P$
$= 800 + 3 P$
$= 800 + 3 \times 50 = 950$ mm of Hg

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Similar questions

Q. A constant temperature and volume

X

decomposes as,

2 X (g) ⟶ 3 Y (g) + 2 Z (g)

P_{X}

is the partial pressure of

X

Observation No.	Time $(m i n)$	$P_{X} (i n m m H g)$
$1$	$0$	$800$
$2$	$100$	$400$
$3$	$200$	$200$

(i)

What is the order of the reaction with respect to

X

(i i)

Find the rate constant.

(i i i)

Find the time for

75

% completion of the reaction.

(i v)

Find the total pressure when pressure of

X

700

m m

H g

Observation no.	Time (in min)	$P_{x} (i n m m H g)$
1	0	800
2	100	400
3	200	200

At constant temperature and volume, $X$ decomposes according to first order kinetics as follows:
$2 X (g) \to 3 Y (g) + 2 Z (g)$
where $P_{x}$ is the partial pressure of $X$ .

Which of the following statements is true for the given reaction?

Observation no.	Time (in min)	$P_{x} (i n m m H g)$
1	0	800
2	100	400
3	200	200

X Y_{2}

dissociates as

X Y_{2} (g) ⇌ X Y (g) + Y (g)

when the initial pressure of

X Y_{2}

is 600 mm of Hg, the total equilibrium pressure is 800 mm of Hg. FInd the value of Equilibrium constant for the reaction assuming that the volume of the system remains unchanged.

Q. For the reaction

2 X (g) \to 2 Y (g) + 2 Z (g)

Time in min.	0	100	200
The partial pressure of X in mm of Hg	800	400	200

Assuming ideal gas nature,

calculate, the order of reaction:

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Observation No.	Time (in minute)	$P_{x}$ (in mm of Hg)
1	0	800
2	100	400
3	200	200