Observations Frequency

1 12

2 11

3 10

4 14

5 13

For the above table, what is the total frequency ?

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Solution

The correct option is C
60
The sum of all frequencies = 12 + 11 + 10 + 14 + 13 = 60

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Similar questions

Q. For the given frequency distribution table , what is the total frequency?

Quantity	Frequency
1	12
2	14
3	15
4	18
5	11

The data is given for 62 students in a certain class regarding their mathematics marks out of 100. Take the classes 0-10, 10-20.. and prepare frequency distribution table and cumulative frequency table more than or equal to type.

55, 60, 81, 90, 45, 65, 45, 52, 30, 85, 20, 10, 75, 95, 09, 20, 25, 39, 45, 50, 78, 70, 46, 64, 42, 58, 31, 82, 27, 11, 78, 97, 07, 22, 2 36, 35, 40, 75, 80, 47, 69, 48, 59, 32, 83, 23, 17, 77, 45, 05, 23, 37, 38, 35, 25, 46, 57, 68, 45, 47, 49.

From the prepared table, answer the following questions :

(i) How many students obtained marks 40 or above 40 ?

(ii) How many students obtained marks 90 or above 90 ?

(iii) How many students obtained marks 60 or above 60 ?

(iv) What is the cumulative frequency of equal to or more than type of the class 0-10?

Q. The weight (in kgs) of 20 student of class IX are recorded as follows.

39	40	37	42	45	51	48	58	50	38
40	39	38	45	46	48	49	52	51	40

prepare a frequency distribution table for the above data.

Look at the frequency distribution table given below:

$\begin{matrix} C l a s s i n t e r v a l & 35 - 45 & 45 - 55 & 55 - 65 & 65 - 75 F r e q u e n c y & 8 & 12 & 20 & 10 \end{matrix}$

The median of the above distribution is

(a) 56.5 (b) 57.5 (c) 58.5 (d) 59

Given below is a cumulative frequency table:
$\begin{matrix} Marks & Number of students Below 10 & 17 Below 20 & 22 Below 30 & 29 Below 40 & 37 Below 50 & 50 Below 60 & 60 \end{matrix}$
Extaract a frequency table from the above.

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Observations Frequency 1 12 2 11 3 10 4 14 5 13 For the above table, what is the total frequency ?

The correct option is C 60The sum of all frequencies = 12 + 11 + 10 + 14 + 13 = 60

Observations Frequency

1 12

2 11

3 10

4 14

5 13

For the above table, what is the total frequency ?

The correct option is C
60
The sum of all frequencies = 12 + 11 + 10 + 14 + 13 = 60