Question

Observe the below graph & calculate:
(a) Average speed of the car in m/s.
(b) Total distance travelled between $5^{th}$ minute and ${45}^{th}$ minute.

Answer 1

(a) Since it is a uniform motion, the average speed is going to be the same as uniform speed.
$Uniformspeed=\frac{dis\tan cecovered}{timetaken}=\frac{(30-20)}{\left(\right(30-20)\times 60)}=\frac{1}{60}m/s=0.0167m/s.$
(b) The time difference between the 5th minute and the 45th minute will be 40 minutes.
As uniform speed is 1 metre per minute.
Therefore, the distance travelled in the time interval of 40 minutes is 40 m.