Question

Observe the figure and find $x$.

Answer 1

We know that, if two angles are complementary, then their sum is ${90}^o$.

Given, the angles are ${40}^o$ and $(6x+2{)}^o$.

Then, their sum: ${40}^o+(6x+2{)}^o={90}^o$.

$⟹$ ${40}^o+6x+2^o={90}^o$

$⟹$ ${42}^o+6x={90}^o$

$⟹$ $6x={90}^o-{42}^o$

$⟹$ $6x={48}^o$

$⟹$ $x=\frac{{48}^o}{6}$

$⟹$ $x=8^o$.