Observe the following distance-time graph:
Identify the respective speeds of the body when it moves from O (origin) to A and B to C.

2 k m h^{- 1}, 4 k m h^{- 1}

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1 k m h^{- 1}, 3 k m h^{- 1}

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3 k m h^{- 1}, 5 k m h^{- 1}

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4 k m h^{- 1}, 6 k m h^{- 1}

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Solution

The correct option is A $2 k m h^{- 1}, 4 k m h^{- 1}$
When body moves from O to A,
Speed = Slope of OA
= $\frac{A D}{O D}$
$= (\frac{2 - 0}{1 - 0}) = 2 k m h^{- 1}$

When body moves from B to C,
Speed = Slope of BC
= $\frac{C G}{B G}$
$= (\frac{4 - 2}{2.0 - 1.5}) = 4 k m h^{- 1}$

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