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Question

Observe the following Lists

List I

List II

A. The number of ways of

answering one or more of n questions

i. nPr2r

B. The number of ways of answering

one or more of n questions is

when each question has an

alternative is

ii. 2n−1

C. The number of circular

permutations of n different

things taken r at a time is

iii. nPrr

D. The number of circular

permutations of n things taken

r at a time none direction is

iv. 3n−1

v. 2n


A
A-ii, B-iv, C-iii, D-i
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B
A-ii, B-iii, C-i, D-iv
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C
A-iii, B-ii, C-i, D-iv
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D
A-iv, B-iii, C-ii, D-i
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Solution

The correct option is D A-ii, B-iv, C-iii, D-i
A. No. of ways of answering one or more questions =nC1+nC2+nC3+nC4+...+nCn

From binomial expansion theroem,
2n=nC0+nC1+nC2+nC3+nC4+...+nCn

2n1=nC1+nC2+nC3+nC4+...+nCn

No. of ways of answering one or more questions out of n questions is 2n1
Option 2

B. No. of ways of answering one question with 2 alternatives = nC1×2
No. of ways of answering two questions with 2 alternatives = nC2×22
.
.
No. of ways of answering r questions with 2 alternatives = nCr×2r
Total no. of ways of answering one or more questions with 2 alternatives =nC1×21+nC2×22+nC3×23+....+nCn×2n

From binomial expansion theorem,
(1+2)n=nC0×20+nC1×21+nC2×22..+nCn×2n
So,
3n1=nC1×21+nC2×22+nC3×23+....+nCn×2n

No. of ways of answering one or more questions with 2 alternatives is 3n1

C. The number of circular permutations of n different things taken r at a time is nPrr

D. The number of circular permutations of n different things taken r at a time when order does not matter is nPr2r

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