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Question

Observe the following statements regarding isotones :
i) 39K19 and 40CA20 are isotones
ii) Nuclides having different atomic numbers (z) and mass number (A) but same number of neutrons (n) are called Isotones
iii) 19F9 and 23NA11 are isotones .
The correct answer is

A
i,ii and iii are correct
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B
i and ii are correct
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C
i and iii are correct
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D
ii and iii are correct
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Solution

The correct option is B i and ii are correct
We know that when nuclides have same number of neutrons (N) but have different mass number (A) and protons number(Z) are called Isotones.
i) For 39K19,Z=19,A=39,N=3919=20 and for 40CA20,Z=20,A=40,N=4020=20
Since both nuclides have same neutrons number so they are isotones.
iii) For 19F9,Z=9,A=19,N=199=10 and for 23NA11,Z=11,A=23,N=2311=12
Since both nuclides have different neutrons number so they are not isotones.
Hence, statement i) and ii) are correct.

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