Question

Observe the given construction, if $\angle BAE={60}^{\circ }$, then $\angle BAC$ will be:

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

$\angle BAE={60}^{\circ }$ [Given]
AF is angle bisector of ${60}^{\circ }.$
$\Rightarrow \angle BAF={30}^{\circ }$
and AC is angle bisector of ${30}^{\circ }.$
$\Rightarrow \angle BAC={15}^{\circ }$