Observe the given construction, if ∠BAE=60∘, then ∠CAF will be
∠BAE=60∘ [Given] AF is angle bisector of 60∘ ⇒∠BAF=30∘ and AC is angle bisector of 30∘
∠BAC=∠CAF ⇒∠BAC=∠CAF=15∘
In the figure, ∠BAE=60∘ and ∠CAF=80∘, then ∠BDA is