Question

Observe the given construction, if $\angle BAE={60}^{\circ }$, then $\angle CAF$ will be

Answer 1

$\angle BAE={60}^{\circ }$ [Given]
AF is angle bisector of ${60}^{\circ }$
$\Rightarrow \angle BAF={30}^{\circ }$
and AC is angle bisector of ${30}^{\circ }$

$\angle BAC=\angle CAF$
$\Rightarrow \angle BAC=\angle CAF={15}^{\circ }$