∠BAE=60∘ AF is angle bisector of 60∘ ⇒∠BAF=30∘ [1 Mark] and AC is angle bisector of 30∘
∠BAC=∠CAF ⇒∠BAC=∠CAF=15∘ [1 mark]
Observe the given construction, if ∠BAE=60∘, then ∠CAF will be