Question

Observe the given figure carefully.

Select the correct statement(s) from the following.
(i) In beaker ‘I’ colourless solution will change to green.
(ii) In beaker ‘2’, colour of solution changes to blue.
(iii) In beaker ‘3’, if ‘Y’ is aluminium then reaction will take place.
(iv) In beaker ‘3’, if ‘Y’ is silver then reaction will not take place.

• A. (II) only
• B. (II) and (IV)
• C. (II) ,(III) and (IV)
• D. (I) and (II)

Answer 1

The correct option is C (II) ,(III) and (IV)

$\bullet$ In beaker 1, since copper is lower than zinc in the reactivity series, it cannot replace zinc from its salt solution so there is no change observed in beaker 1. So, the statement I is incorrect.
$\bullet$ In beaker 2, copper is more reactive than silver, can replace the silver from its solution and the colour of the solution changes to blue. So, statement II is correct.
$\bullet$ In beaker 3, metal Y is dipped in a copper sulphate solution.
$\bullet$ If metal Y is aluminium, which is higher in the reactivity series than copper, the reaction will take place. So, statement III is correct.
$\bullet$ Whereas, if the metal Y is silver, which is less reactive than copper, there will be no reaction. So, the statement IV is correct.