Question

Observe the given reaction carefully and identify (i) , (ii), (iii) and (iv).

• A. $\left(i\right)\text{Reducing agent}\left(ii\right)\text{Oxidation}\left(iii\right)\text{Reduction}\left(iv\right)\text{Oxidising agent}$
• B. $\left(i\right)\text{Oxydising agent}\left(ii\right)\text{Reduction}\left(iii\right)\text{Reduction}\left(iv\right)\text{Reducing agent}$
• C. $\left(i\right)\text{Oxydising agent}\left(ii\right)\text{Reduction}\left(iii\right)\text{Oxydation}\left(iv\right)\text{Reducing agent}$
• D. $\left(i\right)\text{Oxydising agent}\left(ii\right)\text{Oxidation}\left(iii\right)\text{Reduction}\left(iv\right)\text{Reducing agent}$

Answer 1

The correct option is D $\left(i\right)\text{Oxydising agent}\left(ii\right)\text{Oxidation}\left(iii\right)\text{Reduction}\left(iv\right)\text{Reducing agent}$

Here the oxidation of $Cu$ in $CuO$ is $+2$. It is reduced to $Cu$ having oxidation state of zero. So, $CuO$ is an oxidising agent. The process $iii$ is a reduction step.
The $H_2$ having zero oxidation is oxidized to $H_{2}O$ where the oxidation state of $H^{+}$ is $+1$. So, the process $ii$ is oxidation step.