Question

Observe the pattern and complete it.
$(11{)}^2=121(101{)}^2=10201(1001{)}^2=1002001(10001{)}^2=\left(\right)$

• A. 100020001
• B. 10020001
• C. 10020001
• D. 100201

Answer 1

The correct option is A 100020001

Squares of numbers with this form follow a pattern.
Count the number of zeros between the ones at the two ends.
In the above case there are 3 zeroes in between the ones.
$\therefore$ The square of 10001 is:
1 followed by three zeros then 2 and again followed by 3 zeros, 1 at the units place.
i.e 100020001