Observe the pattern given below. 2, 6, 10, 14, ... The algebraic expression for the nth term of the pattern is .
A
4n+2
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B
4n−2
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C
4n−1
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D
2n−2
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Solution
The correct option is B4n−2 Consider the given pattern. 2, 6, 10, 14, ... The first term 2 can be written as 4(1) - 2. The second term 6 can be written as 4(2) - 2. The third term 10 can be written as 4(3) - 2, and so on. So, the nth term of the pattern is given by 4(n)−2. Hence, the algebraic expression for the nth term of the given pattern is 4n−2.