Observer the pattern followed by the numbers and get the general expressions for representing a two-digit number.
Tens Place Ones Place Number Formed Expanded form of the Numbers
$1$ $5$ $15$ $15 = 10 \times 1 + 1 \times 5$
$2$ $7$
$3$ $5$
$7$ $5$
$8$ $2$
$3$ $7$
$7$ $4$

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Solution

$\begin{matrix} Tens place & Ones place & Number formed & Expanded form 1 & 5 & 15 & 15 = 10 \times 1 + 1 \times 5 2 & 7 & 27 & 27 = 10 \times 2 + 1 \times 7 3 & 5 & 35 & 35 = 10 \times 3 + 1 \times 5 7 & 5 & 75 & 75 = 10 \times 7 + 1 \times 5 8 & 2 & 82 & 82 = 10 \times 8 + 1 \times 2 3 & 7 & 37 & 37 = 10 \times 3 + 1 \times 7 7 & 4 & 74 & 74 = 10 \times 7 + 1 \times 4 \end{matrix}$

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Similar questions

Using commutativity and associativity of addition of rational numbers, express each of the following as a rational number:

(i) $\frac{2}{5} + \frac{7}{3} + \frac{- 4}{5} + \frac{- 1}{3}$

(ii) $\frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9}$

(iii) $\frac{2}{5} + \frac{8}{3} + \frac{- 11}{15} + \frac{4}{5} + \frac{- 2}{3}$

(iv) $\frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{21}$

(\frac{- 3}{7}) + \frac{1}{9} = \frac{1}{9} + (\frac{- 3}{7})

\frac{4}{9} + (\frac{7}{8} + \frac{1}{2}) = (\frac{4}{9} + \frac{7}{8}) + \frac{1}{2}

8 + \frac{7}{10} = \frac{7}{10} + 8

(\frac{- 7}{15}) + 0 = \frac{- 7}{15} = 0 + (\frac{- 7}{15})

\frac{2}{5} + (\frac{- 2}{5}) = 0

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