Obtain a relation for the displacement of an object moving with a uniform acceleration in the interval between 4th and 5th seconds. Assume zero initial velocity.
A
92×acceleration
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B
29×acceleration
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C
72×acceleration
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D
52×acceleration
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Solution
The correct option is A92×acceleration From second equation of motion, s=ut+12at2 The displacement after t = 5 seconds will be s5=5u+12a52 The displacement after t = 4 seconds will be s4=4u+12a42 Displacement between 4th and 5th second will be s5−s4=(5u+12a52)−(4u+12a42). =u+12a(25−16)=u+92a =92a