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Question

Obtain all other zeroes of 3x4+6x32x210x5, if two of its zeroes are 53 and 53.

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Solution

p(x)=3x4+6x32x210x5

Since the two zeroes are 53 and 53 ,

(x53)(x+53)=(x253) is a factor of 3x4+6x32x210x5.

Therefore, we divide the given polynomial by x253.

We factorize 3x2+6x+3=0
=3(x2+2x+1)=0

=(x+1)2=0

Therefore, its zero is given by x + 1 = 0.

x = -1

As it has the term (x+1)2 , therefore, there will be 2 zeroes at x = - 1.

Hence, the zeroes of the given polynomial are 53 and 53 and – 1.


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