Obtain all zeros of $f (x) = x^{3} + 13 x^{2} + 32 x + 20,$ if one of its zeros is $- 2$ .

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Solution

$f (x) = x^{3} + 13 x^{2} + 32 x + 20$
$f (- 2) = 0$
$∴ (x + 2)$ is a factor of $f (x)$
$f (x) = (x + 2) (x^{2} + 11 x + 10)$
$= (x + 2) (x + 10) (x + 1)$
$∴$ zeros of $f (x)$ are $- 2, - 10, - 1$

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Similar questions

f (x) = x^{3} + 13 x^{2} + 32 x + 20

If one of the zeros of $f (x) = x^{3} + 13 x^{2} + 32 x + 20$ is $- 2$ then all its zeros are

A. $2, 13, 11$

B. $- 10, - 1, - 2$

C. $4, - 2, - 10$

D. $- 2, 5, 10$

(x) = x^{3} + 13 x^{2} + 32 x + 20,

p (x) = x^{3} - 13 x^{2} + 32 x - 60

10

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