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Wheatstone Bridge

Obtain balanc...

Question

Obtain balancing condition of Wheatstone's bridge Kirchoff's rules electrical circuit.

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Solution

The balancing condition for wheatstone bridge is,
$\frac{R_{p}}{R_{R}} = \frac{R_{Q}}{R_{S}}$
Because of this there is no potential difference between the adjoining points of bridge and thus no current flows through it.

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