Obtain real solutions of simultaneous equations. xy+3y2−x+4y−7=0 2xy+y2−2x−2y+1=0.
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Solution
Multiplying (1) by 2 and subtracting from (2), we get 5y2+10y−15=0 or y2+2y−3=0 or (y+3)(y−1)=0 ∴y=−3 and hence x=2. Note y≠1 as y=1 will make x infinite or reduce the equation to an identify.