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Question
Obtain simple logical expression for the following switching circuit and draw the circuit..(p∧r∨q)∨[∼p∨(q∧∼r)]
Obtain simple logical expression for the following switching circuit and draw the circuit..(p∧r∨q)∨[∼p∨(q∧∼r)]
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Solution
The correct option is B q
p q r ∼p ∼r p∧r p∧r∨q=a (q∧∼r) ∼p∨(q∧∼r)=b a∨b T T T F F T T F F T T T F F T F T T T T T F T F F T T F F T T F F F T F F F F F F T T T F F T F T T F T F T T F T T T T F F T T F F F F T T F F F T T F F F T T
therefore Logical expression of the (p∧r∨q)∨[∼p∨(q∧∼r)] is not q
| p | q | r | ∼p | ∼r | p∧r | p∧r∨q=a | (q∧∼r) | ∼p∨(q∧∼r)=b | a∨b |
| T | T | T | F | F | T | T | F | F | T |
| T | T | F | F | T | F | T | T | T | T |
| T | F | T | F | F | T | T | F | F | T |
| T | F | F | F | T | F | F | F | F | F |
| F | T | T | T | F | F | T | F | T | T |
| F | T | F | T | T | F | T | T | T | T |
| F | F | T | T | F | F | F | F | T | T |
| F | F | F | T | T | F | F | F | T | T |
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