Question

Obtain the binding energy (in MeV) of a nitrogen nucleus $\left({}_7^{14}\text{N}\right)$.

[Given: m $\left({}_7^{14}\text{N}\right)$ =14.00307 u.]

Answer 1

Given:

mass defect. $\Delta m=0.00307u.$

Binding Energy is given by,
$E=\Delta m\times 931MeV$

$=0.00307\times 931=2.86MeV$.