wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Obtain the complex integral:
C2zdz
Where C2 is the straight line path from z=1+i to z=3+3i.
507407_37b69158cfd5426a9f01d2bda2392031.png

A
4+4i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2+4i
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8i
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 8i
C2zdz=[z22]C2
Substituting the upper and lower limits, we get (3+3i)2(1+i)2
=9+18i+9i2(1+2i+i2)2
=9+18i912i+12
=16i2
=8i

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Extrema
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon