Obtain the expression for the self-inductance $(L)$ of the solenoid. Calculate its value.

L = 1.97 \times 10^{- 8} H

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L = 1.97 \times 10^{- 2} H

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L = 1.97 \times 10^{- 12} H

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L = 1.97 \times 10^{- 0} H

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Solution

The correct option is B $L = 1.97 \times 10^{- 2} H$
$L = \frac{μ_{0} N^{2} π r^{2}}{l}$
Value of $L = 1.97 \times 10^{- 2} H$

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