Obtain the product of $2, 4 y, 8 y^{2}, 16 y^{3}$

1045 y^{5}

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1024 y^{6}

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1634 y^{3}

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102 y^{5}

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Solution

The correct option is B $1024 y^{6}$
Product of $2, 4 y, 8 y^{2}, 16 y^{3}$
$= (2) \times (4 y) \times (8 y^{2}) \times (16 y^{3})$
$= 2 \times 4 \times 8 \times 16 \times y^{(1 + 2 + 3)}$ $[∵ a^{m} \times a^{n} = a^{m + n}]$
$= 1024 y^{6}$

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