Obtain the product of -i- 2- 4y- 8y-2 - 16y-3 -ii- a- 2b- 3c- 6abc -iii- m- -mn- mnp - Maths Q-A

Product of 2, 4y, 8y^2, 16y^3 can be obtained as multiplying each term.2× 4y× 8y^2× 16y^30ex0ex=(2× 4× 8× 16)(y×y^2×y^3)0ex0ex=1024 y^1+2+30ex0ex=1024 y^6Hence, ...

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Standard VIII

Mathematics

Multiplying Terms with Same Base

Obtain the pr...

Question

Obtain the product of
$2, 4 y, 8 y^{2}, 16 y^{3}$

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Solution

Product of $2, 4 y, 8 y^{2}, 16 y^{3}$ can be obtained as multiplying each term.
$2 \times 4 y \times 8 y^{2} \times 16 y^{3} = (2 \times 4 \times 8 \times 16) (y \times y^{2} \times y^{3}) = 1024 y^{1 + 2 + 3} = 1024 y^{6}$
Hence, product of $2, 4 y, 8 y^{2}, 16 y^{3}$ is $1024 y^{6}$ .

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Similar questions

Q. Obtain the product of
(i)

x y, y z, z x

(ii)

a, - a^{2}, a^{3}

(iii)

2, 4 y, 8 y^{2}, 16 y^{3}

(iv)

a, 2 b, 3 c, 6 a b c

(v)

m, - m n, m n p

Q. Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.

Dividend		Divisor
(i)	14x² + 13x − 15	7x − 4
(ii)	15z³ − 20z² + 13z − 12	3z − 6
(iii)	6y⁵ − 28y³ + 3y² + 30y − 9	2y² − 6
(iv)	34x − 22x³ − 12x⁴ − 10x² − 75	3x + 7
(v)	15y⁴ − 16y³ + 9y2 − $\frac{10}{3}$ y + 6	3y − 2
(vi)	4y³ + 8y + 8y² + 7	2y² − y + 1
(vii)	6y⁵ + 4y⁴ + 4y³ + 7y² + 27y + 6	2y³ + 1

Q. Divide 15y⁴ + 16y³ +

\frac{10}{3}

y − 9y² − 6 by 3y − 2. Write down the coefficients of the terms in the quotient.

Divide $15 y^{4} + 16 y^{3} + \frac{10}{3} y - 9 y^{2} - 6$ by 3y - 2. Write down the co-efficients of the terms in the quotient.

Obtain the product of

(i) xy, yz, zx (ii) a, − a², a³ (iii) 2, 4y, 8y², 16y³

(iv) a, 2b, 3c, 6abc (v) m, − mn, mnp

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Obtain the product of 2,4y,8y2,16y3

Product of 2,4y,8y2,16y3 can be obtained as multiplying each term.2×4y×8y2×16y3=2×4×8×16y×y2×y3=1024y1+2+3=1024y6Hence, product of 2,4y,8y2,16y3 is 1024y6.

Obtain the product of
$2, 4 y, 8 y^{2}, 16 y^{3}$

Product of $2, 4 y, 8 y^{2}, 16 y^{3}$ can be obtained as multiplying each term.
$2 \times 4 y \times 8 y^{2} \times 16 y^{3} = (2 \times 4 \times 8 \times 16) (y \times y^{2} \times y^{3}) = 1024 y^{1 + 2 + 3} = 1024 y^{6}$
Hence, product of $2, 4 y, 8 y^{2}, 16 y^{3}$ is $1024 y^{6}$ .