Obtain the product of: $m, m n, m n p$

m^{2} n^{3} p

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n^{3} m^{2} p

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m^{3} n^{2} p

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m^{4} n^{2} p

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Solution

The correct option is B $m^{3} n^{2} p$
$m, m n, m n p$
$= m \times m n \times m n p$
$= m^{3} n^{2} p$

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