Question

Obtain the roots of the following quadratic equation by using the general formula the solution:
$25x^2+20x+7=0$

Answer 1

Formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Given,

$25x^2+20x+7=0$

$x=\frac{-20\pm \sqrt{{20}^2-4\cdot 25\cdot 7}}{2\cdot 25}$

$=\frac{-20\pm 10\sqrt{3}i}{50}$

$=\frac{-2\pm \sqrt{3}i}{5}$

$x=-\frac{2}{5}+i\frac{\sqrt{3}}{5},-\frac{2}{5}-i\frac{\sqrt{3}}{5}$