Question

Obtain the roots of the following quadratic equation by using the general formula the solution:
$6x^2+x-2=0$

Answer 1

Formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Given,

$6x^2+x-2=0$

$x=\frac{-1\pm \sqrt{1^2-4\cdot 6(-2)}}{2\cdot 6}$

$=\frac{-1\pm \sqrt{49}}{12}$

$=\frac{-1\pm 7}{12}$

$x=\frac{1}{2},-\frac{2}{3}$