Question

Obtain the roots of the following quadratic equation by using the general formula the solution:
$2x^2-2\sqrt{2}x+1=0$

Answer 1

Formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Given,

$2x^2-2\sqrt{2}x+1=0$

$x=\frac{-(-2\sqrt{2})\pm \sqrt{(-2\sqrt{2}{)}^2-4(2\left)\right(1)}}{2\left(2\right)}$

$=\frac{-(-2\sqrt{2})}{2\cdot 2}$

$x=\frac{\sqrt{2}}{2}$