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Hydrogen Bonding

Of the follow...

Question

Of the following hydrides, which has the lowest boiling point?

N H_{3}

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P H_{3}

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S b H_{3}

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A s H_{3}

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Solution

The correct option is B $P H_{3}$
As we move from top to bottom in the hydrides of a particular group, the boiling point increases as the molecular weight increases, hence, ammonia ( $N H_{3}$ ) should have the least boiling point.
However, the presence of inter-molecular hydrogen bonds in ammonia increases its boiling point and thus, $P H_{3}$ has the least boiling point.

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

15

P H_{3} < A s H_{3} < N H_{3} < S b H_{3} < B i H_{3}

H

N H_{3}

S b

N H_{3}, P H_{3}, A s H_{3}

S b H_{3}

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