Of the following set which one does not contain isoelectronic species?

C N^{-}, N_{2}, {C_{2}}^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P {O_{4}}^{3 -}, S {O_{4}}^{2 -}, C 1 {O_{4}}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B {O_{3}}^{3 -}, C {O_{3}}^{2 -}, N {O_{3}}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S {O_{3}}^{2 -}, C {O_{3}}^{2 -}, N {O_{3}}^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $S {O_{3}}^{2 -}, C {O_{3}}^{2 -}, N {O_{3}}^{-}$
A) $C N^{-} = 14 e^{-}$
$N_{2} = 7 + 7 = 14 e^{-}$
$C_{2}^{2 -} = 12 + 2 = 14 e^{-}$

B) $P O_{4}^{3 -} = 15 + 32 + 3 = 50 e^{-}$
$S O_{4}^{2 -} = 16 + 32 + 2 = 50 e^{-}$
$C l O_{4}^{-} = 17 + 32 + 1 = 50 e^{-}$

C) $B O_{3}^{3 -} = 5 + 24 + 3 = 32 e^{-}$
$C O_{3}^{2 -} = 6 + 24 + 2 = 32 e^{-}$
$N O_{3}^{-} = 7 + 24 + 1 = 32 e^{-}$

D) $S O_{3}^{2 -} = 16 + 24 + 2 = 42 e^{-}$
$C O_{3}^{2 -} = 6 + 24 + 2 = 32 e^{-}$
$N O_{3}^{-} = 7 + 24 + 1 = 32 e^{-}$
So, $S O_{3}^{2 -}, C O_{3}^{2 -}, N O_{3}^{-}$ are not the isoelectronic species.

Suggest Corrections

Similar questions

N O_{3}^{-}, A s O_{3}^{3 -} C O_{3}^{2 -}, C l O_{3}^{-}, S O_{3}^{2 -}

B O_{3}^{3 -}

{N O}_{3}^{-}, A s O_{3}^{3 -}, {C O}_{3}^{2 -}, {C l O}_{3}^{-}, {S O}_{3}^{2 -}

B O_{3}^{3 -}

N O_{3}^{-}, A s O_{3}^{3 -}, C O_{3}^{2 -}, C l O_{3}^{-}, S O_{3}^{2 -}

B O_{3}^{3 -}

N O_{3}^{-}, C O_{3}^{2 -}, C l O_{3}^{-}, S O_{2}

Which among the following are isoelectronic $N O_{3}^{-}, C O_{3}^{2 -}, C l O_{3}^{-}, S O_{2}$

Join BYJU'S Learning Program