Question

Of the four numbers, the first is twice the second, the second is one-third of the third and third is $5$ times the fourth, The average of the numbers is $24.75$. The largest of these number is

• A. $9$
• B. $25$
• C. $30$
• D. $45$

Answer 1

Answer: (D)

$45$

Let the fourth number be $x$.

Then, third number $=5x$
Second number $=$ $\frac{5x}{3}$
First number $=$ $\frac{10x}{3}$
$\therefore x+5x+\frac{5x}{3}+\frac{10x}{3}=(24.75\times 4)=99$
$\Rightarrow 3x+15x+5x+10x=99\times 3$
$\Rightarrow 33x=99\times 3\Rightarrow x=\frac{99\times 3}{33}=9$
$\therefore$ The numbers are $,45,15,30$.
$\Rightarrow$ largest number $=45$