Question

Of the halide ions, $I^{-}$ is the most powerful reducing agent.
If true enter 1, else enter 0.

Answer 1

$X^{-}|X_2|Pt$ electrode	Standard reduction potential (V)
$F^{-}|F_2|Pt$	+2.87
$C{l}^{-}|C{l}_2|Pt$	+1.36
$B{r}^{-}|B{r}_2|Pt$	+1.08
$I^{-}|I_2|Pt$	$+0.535$

Of the halide ions, $I^{-}$ is the most powerful reducing agent. As can be seen from the table, the iodide ion has lowest value of standard reduction potential. Hence, it is most powerful reducing agent among the halide ions.